X^2+60x-14000=0

Solution for X^2+60x-14000=0 equation:

X^2+60X-14000=0

a = 1; b = 60; c = -14000;
Δ = b2-4ac
Δ = 602-4·1·(-14000)
Δ = 59600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{59600}=\sqrt{400*149}=\sqrt{400}*\sqrt{149}=20\sqrt{149}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-20\sqrt{149}}{2*1}=\frac{-60-20\sqrt{149}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+20\sqrt{149}}{2*1}=\frac{-60+20\sqrt{149}}{2}
$